3.169 \(\int x^{3/2} (A+B x^2) (b x^2+c x^4)^2 \, dx\)

Optimal. Leaf size=63 \[ \frac {2}{13} A b^2 x^{13/2}+\frac {2}{21} c x^{21/2} (A c+2 b B)+\frac {2}{17} b x^{17/2} (2 A c+b B)+\frac {2}{25} B c^2 x^{25/2} \]

[Out]

2/13*A*b^2*x^(13/2)+2/17*b*(2*A*c+B*b)*x^(17/2)+2/21*c*(A*c+2*B*b)*x^(21/2)+2/25*B*c^2*x^(25/2)

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Rubi [A]  time = 0.04, antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {1584, 448} \[ \frac {2}{13} A b^2 x^{13/2}+\frac {2}{21} c x^{21/2} (A c+2 b B)+\frac {2}{17} b x^{17/2} (2 A c+b B)+\frac {2}{25} B c^2 x^{25/2} \]

Antiderivative was successfully verified.

[In]

Int[x^(3/2)*(A + B*x^2)*(b*x^2 + c*x^4)^2,x]

[Out]

(2*A*b^2*x^(13/2))/13 + (2*b*(b*B + 2*A*c)*x^(17/2))/17 + (2*c*(2*b*B + A*c)*x^(21/2))/21 + (2*B*c^2*x^(25/2))
/25

Rule 448

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Int[ExpandI
ntegrand[(e*x)^m*(a + b*x^n)^p*(c + d*x^n)^q, x], x] /; FreeQ[{a, b, c, d, e, m, n}, x] && NeQ[b*c - a*d, 0] &
& IGtQ[p, 0] && IGtQ[q, 0]

Rule 1584

Int[(u_.)*(x_)^(m_.)*((a_.)*(x_)^(p_.) + (b_.)*(x_)^(q_.))^(n_.), x_Symbol] :> Int[u*x^(m + n*p)*(a + b*x^(q -
p))^n, x] /; FreeQ[{a, b, m, p, q}, x] && IntegerQ[n] && PosQ[q - p]

Rubi steps

\begin {align*} \int x^{3/2} \left (A+B x^2\right ) \left (b x^2+c x^4\right )^2 \, dx &=\int x^{11/2} \left (A+B x^2\right ) \left (b+c x^2\right )^2 \, dx\\ &=\int \left (A b^2 x^{11/2}+b (b B+2 A c) x^{15/2}+c (2 b B+A c) x^{19/2}+B c^2 x^{23/2}\right ) \, dx\\ &=\frac {2}{13} A b^2 x^{13/2}+\frac {2}{17} b (b B+2 A c) x^{17/2}+\frac {2}{21} c (2 b B+A c) x^{21/2}+\frac {2}{25} B c^2 x^{25/2}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 63, normalized size = 1.00 \[ \frac {2}{13} A b^2 x^{13/2}+\frac {2}{21} c x^{21/2} (A c+2 b B)+\frac {2}{17} b x^{17/2} (2 A c+b B)+\frac {2}{25} B c^2 x^{25/2} \]

Antiderivative was successfully verified.

[In]

Integrate[x^(3/2)*(A + B*x^2)*(b*x^2 + c*x^4)^2,x]

[Out]

(2*A*b^2*x^(13/2))/13 + (2*b*(b*B + 2*A*c)*x^(17/2))/17 + (2*c*(2*b*B + A*c)*x^(21/2))/21 + (2*B*c^2*x^(25/2))
/25

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fricas [A]  time = 0.80, size = 56, normalized size = 0.89 \[ \frac {2}{116025} \, {\left (4641 \, B c^{2} x^{12} + 5525 \, {\left (2 \, B b c + A c^{2}\right )} x^{10} + 8925 \, A b^{2} x^{6} + 6825 \, {\left (B b^{2} + 2 \, A b c\right )} x^{8}\right )} \sqrt {x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)*(B*x^2+A)*(c*x^4+b*x^2)^2,x, algorithm="fricas")

[Out]

2/116025*(4641*B*c^2*x^12 + 5525*(2*B*b*c + A*c^2)*x^10 + 8925*A*b^2*x^6 + 6825*(B*b^2 + 2*A*b*c)*x^8)*sqrt(x)

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giac [A]  time = 0.17, size = 53, normalized size = 0.84 \[ \frac {2}{25} \, B c^{2} x^{\frac {25}{2}} + \frac {4}{21} \, B b c x^{\frac {21}{2}} + \frac {2}{21} \, A c^{2} x^{\frac {21}{2}} + \frac {2}{17} \, B b^{2} x^{\frac {17}{2}} + \frac {4}{17} \, A b c x^{\frac {17}{2}} + \frac {2}{13} \, A b^{2} x^{\frac {13}{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)*(B*x^2+A)*(c*x^4+b*x^2)^2,x, algorithm="giac")

[Out]

2/25*B*c^2*x^(25/2) + 4/21*B*b*c*x^(21/2) + 2/21*A*c^2*x^(21/2) + 2/17*B*b^2*x^(17/2) + 4/17*A*b*c*x^(17/2) +
2/13*A*b^2*x^(13/2)

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maple [A]  time = 0.05, size = 56, normalized size = 0.89 \[ \frac {2 \left (4641 B \,c^{2} x^{6}+5525 A \,c^{2} x^{4}+11050 B b c \,x^{4}+13650 A b c \,x^{2}+6825 B \,b^{2} x^{2}+8925 b^{2} A \right ) x^{\frac {13}{2}}}{116025} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(3/2)*(B*x^2+A)*(c*x^4+b*x^2)^2,x)

[Out]

2/116025*x^(13/2)*(4641*B*c^2*x^6+5525*A*c^2*x^4+11050*B*b*c*x^4+13650*A*b*c*x^2+6825*B*b^2*x^2+8925*A*b^2)

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maxima [A]  time = 1.30, size = 51, normalized size = 0.81 \[ \frac {2}{25} \, B c^{2} x^{\frac {25}{2}} + \frac {2}{21} \, {\left (2 \, B b c + A c^{2}\right )} x^{\frac {21}{2}} + \frac {2}{13} \, A b^{2} x^{\frac {13}{2}} + \frac {2}{17} \, {\left (B b^{2} + 2 \, A b c\right )} x^{\frac {17}{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)*(B*x^2+A)*(c*x^4+b*x^2)^2,x, algorithm="maxima")

[Out]

2/25*B*c^2*x^(25/2) + 2/21*(2*B*b*c + A*c^2)*x^(21/2) + 2/13*A*b^2*x^(13/2) + 2/17*(B*b^2 + 2*A*b*c)*x^(17/2)

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mupad [B]  time = 0.05, size = 51, normalized size = 0.81 \[ x^{17/2}\,\left (\frac {2\,B\,b^2}{17}+\frac {4\,A\,c\,b}{17}\right )+x^{21/2}\,\left (\frac {2\,A\,c^2}{21}+\frac {4\,B\,b\,c}{21}\right )+\frac {2\,A\,b^2\,x^{13/2}}{13}+\frac {2\,B\,c^2\,x^{25/2}}{25} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(3/2)*(A + B*x^2)*(b*x^2 + c*x^4)^2,x)

[Out]

x^(17/2)*((2*B*b^2)/17 + (4*A*b*c)/17) + x^(21/2)*((2*A*c^2)/21 + (4*B*b*c)/21) + (2*A*b^2*x^(13/2))/13 + (2*B
*c^2*x^(25/2))/25

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sympy [A]  time = 20.95, size = 80, normalized size = 1.27 \[ \frac {2 A b^{2} x^{\frac {13}{2}}}{13} + \frac {4 A b c x^{\frac {17}{2}}}{17} + \frac {2 A c^{2} x^{\frac {21}{2}}}{21} + \frac {2 B b^{2} x^{\frac {17}{2}}}{17} + \frac {4 B b c x^{\frac {21}{2}}}{21} + \frac {2 B c^{2} x^{\frac {25}{2}}}{25} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(3/2)*(B*x**2+A)*(c*x**4+b*x**2)**2,x)

[Out]

2*A*b**2*x**(13/2)/13 + 4*A*b*c*x**(17/2)/17 + 2*A*c**2*x**(21/2)/21 + 2*B*b**2*x**(17/2)/17 + 4*B*b*c*x**(21/
2)/21 + 2*B*c**2*x**(25/2)/25

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